Question

one factor of-x²-x√3+6​

Answer 1

Answer:(3+-√21i)/2

Step-by-step explanation:

X=[-b+-√(b^2-4ac)]/2a

Here we have a=1,b=-√3, c=6 put these value in formula and we get X=(3+-√21i)/2

Answer 2

Step-by-step explanation:

Answer

Given : −x

2

+x

3

+6

Writing this as,

−(x

2

−x

3

)+6

⇒−(x

2

−x

3

+

4

3

)+

4

3

+6

⇒−(x−

2

3

)

2

+

4

27

∵a

2

−2ab+b

2

=(a−b)

2

)

⇒(

2

3

3

)

2

−(x−

2

3

)

2

⇒(

2

3

3

+x−

2

3

)(

2

3

3

−x+

2

3

∵a 2−b 2

=(a+b)(a−b)

∴ Factors are (x+ 3 ) and (2 3 −x)