Question

one farmer is walking in side of 10 meter farm.he complete one round in 40 s .so at 2 minutes and 20 second how much round complete by farmer?​

Answer 1

Answer:

Explanation:

Given side of square =10m, thus perimeter P=40m

Time taken to cover the boundary of 40 m =40 s

Thus in 1 second, the farmer covers a distance of 1 m

Now distance covered by the farmer in 2 min 20 seconds = 1×140=140m

Now the total number of rotation the farmer makes to cover a distance of 140 meters =  

perimeter

totaldistance

​

 

=3.5  

At this point, the farmer is at a point say B from the origin O

Thus the displacement s=  

10  

2

+10  

2

 

​

 from Pythagoras theorem.

s=10  

2

​

=14.14m