Question

one fill pipe A is 3 time faster that second fill pipe B and take 32 minutes less than the fill pipe B. When will the cistern be full of both pipes are opened Together?

Answer 1

Answer:

Step-by-step explanation:

Pipe A is 3 times faster than pipe b

Let time taken by pipe be x.

Therefore time taken by pipe A is x/3

Now, work done by pipe A in one minute =1/x/3=3/x

Works done by pipe b in 1 minute =1/x

Now it is also given that A takes 32 minutes less than b

Therefore,

3/x=1/x-32 (32 is in denominator)

On cross multiplying,

3x-96=x

=2x=96

X=96/2=48

Therefore world done by B in one minute=1/48

Works one by A =3/48

Together , amount of work done in one minute in 1/48+3/48

=4/48

Therefore, they will fill the tank in 48/4=12 minutes