Question

one fo the two digits of a two digit number is three times the other digit if we interchange the of this two - digits and add the resulting number to original number you get 88 what is the original number

Answer 1

Let the number be 10x+y

Then according to the question

10x+y + 10y+x = 88

11x+11y=88

x+y=8

[Also, given that x=3y]

3y+y=8

4y=8

y=2 and x =6

The original number is 62