Question

one fourth of a first order reaction is completed in 15 min find out the half life period of first order reaction​

Answer 1

Answer:

here t symbolizes one fouth of a first order reaction

Explanation:

t=2.303 ×㏒[R.]

     K                [R.]/4

t=2.303 ×㏒4[R.]

    K               [R.]

t=2.303×2㏒2

     K

t=2.303×(2×0.30103)

      K

t=2×0.693  

         k

t=2×half life of a first order reaction [half life of a 1st order reaction =0.693

                                                                                                                   K]

so,t=2×15min

      =30min

      =1800s

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