one fourth of a no. exceeds one fifth of its succesding no. by 3 find the no.
Answers
Answer:
3
Step-by-step explanation:
convert the problem to algebaric equation:
Let the number = x
One fourth of the number = ( 1/4 ) × x = x / 4
Succeeding number of x = ( x + 1 )
One fifth of the above number = ( 1/5 ) × ( x + 1 )= ( x + 1 ) / 5
According to the problem ,
One fourhth of a number exceeds one fifth of its
succeeding number by 3.
x / 4 - ( x + 1 ) /5 = 3
LCM ( 4 , 5 ) = 4 × 5 = 20
[ 5x - 4 ( x + 1 ) ] / 20 = 3
5x - 4x - 4 = 3 × 20
x - 4 = 60
x = 60 + 4
x = 64
Therefore ,
Required number = x = 64
Verification:
x /4 - ( x + 1 ) /5 = 64 /4 - ( 64 + 1 ) / 5
= 16 - 13
=3
Hope it helps :)
Answer:
Step-by-step explanation:
Answers
Hi ,
We have to convert the given word problem into
algebraic equation.
Let the number = x
One fourth of the number = ( 1/4 ) × x = x / 4
Succeeding number of x = ( x + 1 )
One fifth of the above number = ( 1/5 ) × ( x + 1 )= ( x + 1 ) / 5
According to the problem ,
One fourhth of a number exceeds one fifth of its
succeeding number by 3.
x / 4 - ( x + 1 ) /5 = 3
LCM ( 4 , 5 ) = 4 × 5 = 20
[ 5x - 4 ( x + 1 ) ] / 20 = 3
5x - 4x - 4 = 3 × 20
x - 4 = 60
x = 60 + 4
x = 64
Therefore ,
Required number = x = 64
Verification:
x /4 - ( x + 1 ) /5 = 64 /4 - ( 64 + 1 ) / 5
= 16 - 13
= 3
I hope this helps you.
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