Question

One-fourth of a number exceeds one-seventh of itself by 24. Find the number.​

Answer 1

Let the number be x.

One fourth of the number will be x/4 and one seventh of the number will be x/7.

According to the question, x/4 exceeds x/7 by 24.

So, we can write,

x/4 - x/7 = 24

Taking LCM,

3x/28 = 24

By cross multiplication,

x = (24 x 28) / 3

The number is 224.

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Answer 2

${\huge {\bold{\underline{\green {Answer:}}}}}$

Let the number be x.

One fourth of the number = x/4

And, one seventh of it = x/7

It is given that one fourth exceeds its one seventh by 24.

So,

=x/4 - x/7 = 24

=$\frac{7x}{28} - \frac{4x}{28} = 24$

=3x/28 = 24

=x = $\frac{24 \times 28}{3} \\ x = 8 \times 28$

=x = 224

Hence, the number is 224.

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