Question

One fourth of a pole is painted red, one-fifth black, one-third white, whereas the remaining portion is
1.3 metres long. What is the total length of the pole?​

Answer 1

Answer:

let length of the pole be x.

red = x/4

black = x/5

white = x/3

remaining = 1.3 m

x/4 + x/5 + x/3 = 1.3

x(1/4 + 1/5 + 1/3) = 1.3

x(( 15+12+20)/60) = 1.3

x(37/60) = 1.3

x = (1.3)(60/37) = 78/37 m

Answer 2

Let the length of pole be x.

$Red Portion=\frac{x}{4}\\Black Portion=\frac{x}{5}\\White portion=\frac{x}{3}\\Total Painted Portion=\frac{x}{4}+\frac{x}{3}+\frac{x}{5}\\=\frac{15x+20x+12X}{60}\\=\frac{47x}{60}\\Remaining Portion=1.3\\x - Total Painted Portion=1.3\\x-\frac{47x}{60}=1.3\\\\\frac{60x-47x}{60}=1.3\\\frac{13x}{60}=1.3\\x=\frac{13}{10}\times\frac{60}{13}\\x=6$

So the length of the pole of 6 meters.