Question

One fourth of the sum of n and 8 minus the product of hand b.

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Answer 1

Answer:

The answer is

1/4(n+8)-h×b

Answer 2

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Sum of n and 8= n+8

$\sf \frac{1}{4} \:of \:n + 8 = \frac{1}{4} \times n + 8 = > 1n + 2$ minus h×b=> 1n+2-hb

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