Question

One _fourth of x is added to twice x^2

Answer 1

Answer:

The answer is $x=0$ or $x=\frac{1}{8}$

Step-by-step explanation:

Converting given statement in equation form

           $\Rightarrow \frac{1}{4}\times x=2\times x^2\\\Rightarrow x=8x^2\\\Rightarrow 8x^2-x=0\\\Rightarrow x(8x-1)=0\\\Rightarrow x=0 \text{ or } 8x-1=0\\\Rightarrow x=0 \text{ or } 8x=1\Rightarrow x=\frac{1}{8}$