Question

one gm mixture of CaCO3 and NaCl reacts completely with 100ml of N/10 HCl . the percentage of caco3 in the mixture is​

Answer 1

Answer:

Given-

Volume of $HCl$ = 100ml

Mass of $CaCO_{3} + HCl$ is $0.1gm$

Molar mass of $CaCO_{3}$ is $\frac{100g}{mol}$

To find- percentage of $CaCO_{3}$

Explanation:

⨳ According to the question, when 1 mole of CaCO3 is reacts with 2 mole of HCl then the reaction is

$CaCO_{3} + 2HCl$ → $CaCl_{2} + CO_{2} + H_{2}O$

⨳ Molarity of $HCl$ is

$MOLARITY = \frac{No. \ of \ moles }{Volume \ in \ L}$

$No \ of \ moles = 0.1 \times 0.1$

So the molarity of HCl is 0.01 mol.

Now, Mass of $CaCO_{3}$ is $= \frac{No. \ of \ moles }{molar \ mass}$

⨳ Mass of $CaCO_{3} = No. \ of \ moles \times molar \ mass \ of \ CaCO_{3}$

$0.05 \times 100 = 0.5gm$

⨳ So, the percentage of $CaCO_{3}$ is $0.5 \times 100 = 50$

The percentage of CaCO3 is 50% in the mixture.