Question

one gram atom of an element contains 6.023×10^23 atoms
a) find the number of oxygen atom in 4gm of O2
b) which is havier , one oxygen atom or 10 hydrogen atom ?????

Answer 1

any molcule of element contain 6.023 into 10 to the power 23 atoms .

$1mole \: = 6.023 \times {10}^{23} atom$

o2 molecules has mass

$=$

$16 \times 2 = 32$

$\frac{4}{32} \times 6.023 \times {10}^{23}$

you get your answer

Answer 2

Answer:

Explanation:

Here's your answer in the pic