One gram molecule of oxygen is heated at constant pressure from 0°C. What amount of heat should be imparted to the gas to double it's volume? Given cp = 0.218 cal g-1 0 C-1.
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Answer:
The answer is 7962.5 J
Explanation:
First see image,
now from 1st law of thermodynamics,
Q = W + ∆U
⇒Q = RT₀ + RT₀/(γ - 1)
for oxygen (diatomic molecule),
γ = 1.4
= 25/3 × 273 + 25/3 × 273/(1.4 - 1) J
= 2275 + 2275/0.4
= 2275 + 5687.5
= 7962.5 J
Therefore heat required to the gas to double its volume is 7962.5 J
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