one gram of ice at zero degree Celsius is added to 5 grams of water at 10 degree Celsius if the latent heat of the ice b80 calorie per gram the final temperature of the mixture is what urgent...
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The heat energy released by water when it comes at 0`C = mct
= 5*2*10 = 100 cal
Heat energy absorbed by water = mL = 1*80 = 80 cal
Thus all ice is converted to water, and 20 calorie energy is left.
Total mass of water = 5+1 = 6 gms.
Change in energy = mct
20 = 6*2* t (t=change in temp)
20/12 = t
t=1.6'C
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