Question

one gram of magnesium atom in vapour stage absorbs 50kJ energy find the composition of Mg+ and Mg++ found as a result of absorption energy IE1and IE2 for mg are 740 and 1450KJ /mol respectively
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Answer 1

Answer:

Mg+ = 0.35g

Mg++ =0.65g

Explanation:

IE1 for 1g of Mg = 740÷24 = 30.83kJ

similarly, IE2 = 60.41kJ

Mg ---------> Mg+ + e–

x x.

Mg ----------> Mg++ +2e–

1-x. 1-x

so, for x g, IE1 = 30.83x

for 1-x g, IE2 = 60.41(1-x)g. = 60.41- 60.41x

since total energy is 50kJ,

adding both equations, we get,

30.83x + 60.41- 60.41x = 50

-29.58x = -10.41

x= 0.35

1-x= 0.65