One gram of metal hydroxide gives x g of the metal oxide then equivalent weight of metal is
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Answered by
19
Hi I'm Anam, I hope my my answer helps you;
the equivalent weight of the metal is (1-x)g as this is the amount of hydrogen released and the equivalent weight of a metal is equal to the amount of the hydrogen released by a metal.
Answered by
47
Hey there,
● Answer -
(17x-8)/(1-x)
● Explaination -
Let E be equivalent mass of metal and m be no of equivalents reacted.
One equivalent of the metal reacts with one mole of hydroxide, i.e., 17g
m(E+17) = 1 g ...(1)
Also, one equivalent of the metal reacts with 1/2 mole oxygen atoms, i.e., 8 g
m(E+8) = x g ...(2)
Dividing (1) by (2),
(E+17) / (E+8) = 1 / x
xE + 17x = E + 8
E = (17x-8)/(1-x)
Therefore, equivalent weight of metal is (17x-8)/(1-x).
Hope this helps you...
● Answer -
(17x-8)/(1-x)
● Explaination -
Let E be equivalent mass of metal and m be no of equivalents reacted.
One equivalent of the metal reacts with one mole of hydroxide, i.e., 17g
m(E+17) = 1 g ...(1)
Also, one equivalent of the metal reacts with 1/2 mole oxygen atoms, i.e., 8 g
m(E+8) = x g ...(2)
Dividing (1) by (2),
(E+17) / (E+8) = 1 / x
xE + 17x = E + 8
E = (17x-8)/(1-x)
Therefore, equivalent weight of metal is (17x-8)/(1-x).
Hope this helps you...
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