Question

One gram of metallic oxide upon reduction gives 0.68g of the metal. Then what is the equivalent mass of the metal ?

Answer 1

Explanation:

Given,

MO → M

1g 0.68g

Therefore, mass of oxygen = 1 – 0.68 = 0.32 g

So,

0.68 g of metal combines with 0.32 g of oxygen in the metal oxide or 68g of metal combines with 32g of oxygen in the metal oxide.

Therefore,