Question

One gram of mixture of potassium and sodium chlorides on treatment with excess of silver nitrate gave 2g of AgCl. what waw the composition of the two salts in the original mixture

Answer 1

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HERE IS THE ANSWER ⤵⤵⤵⤵

Here, given that, mass of NaCl + mass of KCl = 1.000 g

Let, x = grams of NaCl in original mixture so,  (1-x) = grams of KCl in original mixture

Therefore:

(x) + (1-x) = 1.000 g

Now, moles of NaCl = given mass/molar mass = x/ 58.5 moles

Similarly moles of KCl = (1-x)/ 74.5 moles

Since, KCl and NaCl are in 1:1 ratio, so the 

Mass of AgCl produced by given mole of NaCl =  (x/ 58.5 ) x 143.5 = 2.45 x gm

so, mass of AgCl produced by given moles of KCl = [(1-x)/ 74.5] x 143.4 = 1.92 (1-x) gm

So, the total mass of AgCl produced will be,

2.45 x + 1.92(1-x) = 2

2.45 x + 1.92- 1.92x = 2

0.53 x = 0.08

or, x = 0.150 gm

So, mass of NaCl = 0.15gm

and mass of KCl = 1-x =1-0.15 = 0.85 gm

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