Question

One gram of steam at 100degree celcius is mixed with 5 gram of ice at 0 degree Celsius. What would be the final temperature of mixture.

Answer 1

Answer:

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Class 11

>>Physics

>>Thermal Properties of Matter

>>Calorimetry

>>5 g of steam at 100^o C is mixed with 5

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5g of steam at 100

o

C is mixed with 5g of the ice at 0

o

C. The final temperature of the mixture is?

Medium

Solution

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Correct option is A)

Heat energy required for5gm of water at 0

∘

Cto get converted to water at 100

∘

C is latent heat required + heat required to change its temperature by 100

∘

=(80⋅5)+(5⋅1⋅100)=900calories.

Now,heat liberated by 5gm of steam at 100

∘

C to get converted to water at 100

∘

C is 5⋅537=2685 calories

So,heat energy is enough for 5gm of ice to get converted to 5gm of water at 100

∘

C

So,only 900 calories of heat energy will be liberated by steam,so amount of steam that will be converted to water at the same temperature is 900537=1.66g

So,the final temperature of the mixture will be 100

∘

C