Question

one gram of water at 80^0C is mixed with one gram of ice at 0^0C . the resultant temperature is

Answer 1

Answer:

0 degree Celsius.

Explanation:

Let us assume that the complete ice melts and final temperature is T. Then, by principle of calorimetry,

1(1)(80−T)=1(80)+1(0.5)(T−0)

80−T=80+0.5T

T=0 degree Celsius.

Hence, all the ice just melts and final temperature is 0 degree Celcius.

Answer 2

Answer:

all the ice just melts and final temperature is 0°C.

Explanation:

1(1)(80−T)=1(80)+1(0.5)(T−0)

80−T=80+0.5T

T=0°C