Question

One gram sample of CaCO3 reacts completely with 10ml of 1M HCl solution. What is %purity of sample? (Assume that impurity does not react with acid)

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Answer 1

QUESTION:-

One gram sample of CaCO3 reacts completely with 10ml of 1M HCl solution. What is %purity of sample? (Assume that impurity does not react with acid)

EXPLANATION:-

In this question the case if of limiting reagent

After reaction of HCL and NaOH ,HCL REMAINING =0.01 moles

Total HCL=0.02 moles

So HCL USED =0.02-0.01

==>0.01 MOLES

And moles of CaCO3 used=0.005 which is half of provided

So percentage of purity is simply 50 %

Answer 2

Answer: The answer will be 50%

Explanation:

It should be noted that 100 g of sample contains 80 g of pure $CaCO_{3}$ , so, when 1 g of Calcium chloride the pure sample will be less than 1 g.

When Calcium carbonate reacts with the Hydrochloric acid, the reaction proceeds as:

$CaCO_{3} + 2 HCl$ ⇒ $CaCl_{2}+ CO_{2} + H_{2} O$

It is given in the question that amount of 1 ml of 1 M HCl.

Hence,

10ml of HCl = 0.01 moles

But in the chemical equation, it is clear that 2 moles of HCl is required to proceed the reaction.

So, 2gm of HCl = 0.02 moles

Amount of Calcium carbonate used = 0.005 moles

Hence, the purity of the sample is 50%