one has a few shwep and chickens. when counted one day, they were found to have a total of 45 heads and 120 legs. so what is the number of sheep?
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Answer:
X = sheep
Y = chickens
Legs = 4X + 2Y
Heads = X + y ( we assume no 2 headed chickens )
90 = 4X + 2 Y =(divide both sides by 2 and reorder)=> 2X + Y = 45
32 = X + Y =( solve for Y in terms of X by subtracting X from both sides)=> Y = 32 - X
Substitute Y from the second equation into the first equation
2X + 32 - X = 45 =(subtract 32 from both sides )=> 2X - X = 13 =(factor out X on the left)=> X(2-1) = 13 or X = 13
13 Sheep which gives is (32 - 13 or) 19 chicken
13 sheep + 19 chickens = 32 heads
4 legs / sheep * 13 sheep + 2 legs / chicken * 19 chickens = 52 + 38 = 90 Legs
Step-by-step explanation:
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