Math, asked by Naseerullah97, 6 hours ago

One has invested Rs. 6000/- in two parts. One part is at 9% and other part is at 6% to get same amount. What are the amounts invested?​

Answers

Answered by rishimahajan786
0

Step-by-step explanation:

Let one part is x and other part is (6000−x)

Now,

S.I on first part =S.I. on second part

100

12

×

12

9

=(6000−x)×

100

10

×

2

3

∴x=3750

and (6000−x)

⇒6000−3750=2250

Therefore two parts of 6000 are 3750 and 2250.

Similar questions