Question

One hoff factor of hg2cl2 in aqueous solution will be

Answer 1

If there is 100%dissociation then the hoff mann factor of Hg2Cl2 is 3 because it dissociates into 3 ions.
I hope it will help u..

Answer 2

answer : i = $1+2\alpha$, where $\alpha$ is degree of dissociation.

explanation : Van't Hoff's factor is used to express extent of dissociation or association.for dissociation reaction, An ⇔ nA

Van't Hoff's factor, i = 1 - $\alpha$ + $n\alpha$

where $\alpha$ is degree of dissociation.

now, come to the question,

in aqueous solution, Hg2Cl2 dissociates into (Hg2)²+ and 2Cl- ions.

so, total number of ions, n = 3

so, Van't Hoff's factor, i = 1 - $\alpha$ + 3$\alpha$

= 1 + 2$\alpha$

now, if degree of dissociation is 100% . then,$\alpha$ = 1 and then Van't Hoff's factor will be i = 1 + 2 = 3.