Math, asked by Vsnigdha, 3 months ago

one
If one of the zeros of 2x^2-kx-12
is - 4 then find the value of k?​

Answers

Answered by Anantsharma01
1

Step-by-step explanation:

this is your required answer

Attachments:
Answered by rkcomp31
1

Answer:

k=5

Step-by-step explanation:

let f(x)=2x²-kx-12

-4 is zero of F(x)

so f(-4)=0

so 2(-4)²-k(-4)-12=0

32-4k-12=0

4k=20

k==20/4=5

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