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If one of the zeros of 2x^2-kx-12
is - 4 then find the value of k?
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Step-by-step explanation:
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Answered by
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Answer:
k=5
Step-by-step explanation:
let f(x)=2x²-kx-12
-4 is zero of F(x)
so f(-4)=0
so 2(-4)²-k(-4)-12=0
32-4k-12=0
4k=20
k==20/4=5
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