Question

One integer is 30 more than another integer. If the difference between the larger and twice the smaller is 8 , find the integers.

Answer 1

Answer:

The Integers Are 22 & 52

Step-by-step explanation:

Let the Integers be x and y , also Let Bigged integer be x and smaller integer be y.

$difference \: in \: integer \: is \: 30 \\ = )x - y = 30 \\ = )x = 3 0+ y$

As Per question:-

$difference \: between \: bigger \: integer \: and \: \\ twice \: of \: smaller \: integer \: is \: 8 \\ = )x - 2y = 8 \\ = )30 + y - 2y = 8 \: \: \: \: (x = 30 + y) \\ = ) - y = 8 - 30 \\ = ) - y = - 22 \\ = )y = 22$

Thus,The Number are:-

• y = 22
• x =) y + 30 = 22 + 30

=)52

Hope it helped