one integer is 30 more than another integer. if the difference between the larger and twice the smaller is 8, find the integer.
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let the first integer be X
let the second integer be X+30
A.T.Q.
X+30-2x=8
-x+30=8
-x=-30+8
-x=-22
X=-22/-1
X=22
therefore, first integer is 22
second integer is 22+30=52
let the second integer be X+30
A.T.Q.
X+30-2x=8
-x+30=8
-x=-30+8
-x=-22
X=-22/-1
X=22
therefore, first integer is 22
second integer is 22+30=52
mukul568:
wrong answer
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