Question

one integer is 5 more than twice another integer. the squares of these two integers have a difference of 312?

Answer 1

Answer:

$(2x + {5})^{2} - {x}^{2} = 312 \\ 4 {x}^{2} + 20x + 25 - {x}^{2} = 312 \\ 3 {x}^{2} + 20x - 287 = 0 \\ x = - \frac{41}{3} or \: x = 7$

since x is an integer,the number involved are 7 and 19

thank you..