Question

One is asked to say a three digit number. what is the probability that the number is multiple of 6​

Answer 1

Answer:

0or 1 because probability is always form of. 0or1

Answer 2

Answer:

Sample Space (S) = all the 3-digit number

Event A = all the possible 3-digit numbers multiple of 6

P(A)= n(A)/n(S)

So, the three-digit number starts from 100 and goes on up to 999

The total number of 3 digit number is (999–100+1)= 900 n(S)

the least 3-digit number that is a multiple of 6 is 102

the largest 3-digit number multiple of 6 is 996

The 3-digit numbers multiple of 6 forms an Arithmetic Progression. And for AP we know that

Tn = a + (n-1)d

where

Tn = nth term of an AP

a = the first term

d = common difference

Using the above formula to solve the problem when Tn = 996, a=102, d = 6

996 = 102 + (n-1)6

Rearranging the terms,

n-1 = (996–102)/6

n-1 = 149

n = 150

So, there are 150 3-digit number that is multiple of 6 n(A)

P(A) = 150/900 = 1/6 = 0.1667

Therefore, there is 0.1667 probability that when asked a person to choose a 3-digit number he chooses a multiple of 6

hope it's helpful dear mark as brainliest plss