One is asked to say a two-digit number . What is the probability of it being a prime number
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Answer:
\large{ \textsf{\textbf {\pink {➸ \: \: Question \: :-}}}}➸ Question :-
50 identical circular plates are placed one above the other to form a solid cylinder. For each plate, diameter = 21cm and thickness = 1.5cm.
Find :-
Curved surface area of the cylinder formed.
Volume of the cylinder formed.
\begin{gathered} \\ \end{gathered}
\large {\textsf{ \textbf {\pink {➸ \: \: Solution \: :-}}}} ➸ Solution :-
Given :-
50 plates each with diameter = 21cm
Radius = \sf \cfrac {21}{2}
2
21
cm
Thicknesses of each plate = 1.5cm
Total thickness of the plates = 1.5cm × 50 = 75cm
\boxed {\rm \bold \blue {CSA \: of \: a \: cylinder=2\pi rh}}
CSAofacylinder=2πrh
\blue ➸ \: \: \: \sf 2( \cfrac{22}{7} )( \dfrac{21}{2} )(75)➸2(
7
22
)(
2
21
)(75)
\blue ➸ \: \: \: \sf\cancel{ 2} \times \cfrac{22}{7} \times \cfrac{21}{\cancel2} \times 75➸
2
×
7
22
×
2
21
×75
\blue ➸~~~\sf \cfrac{22 \times 21 \times 75}{7}➸
7
22×21×75
\blue ➸ \: \: \: \sf \cfrac{34,650}{7}➸
7
34,650
\blue ➸~~~\sf CSA = 4950~cm^2➸ CSA=4950 cm
2
\boxed {\bold \blue{Volume \: of \: a \: cylinder =\pi r^2h} }
Volumeofacylinder=πr
2
h
\blue➸ \: \: \: \sf \cfrac{22}{7} ( \cfrac{21}{2} )( \cfrac{21}{2} )(75)➸
7
22
(
2
21
)(
2
21
)(75)
\blue ➸ \: \: \: \sf \cfrac{\cancel{22}}{7} \times \cfrac{21}{\cancel2} \times \cfrac{21}{2} \times 75➸
7
22
×
2
21
×
2
21
×75
\blue➸ \: \: \: \sf \cfrac{3,63,825}{14}➸
14
3,63,825
\blue➸ \: \: \: \sf Volume=25987.5~cm^3➸Volume=25987.5 cm
3
\begin{gathered} \\ \end{gathered}
\large {\textsf {\textbf \pink {➸ \: \: Know \: more \: :-}}}➸ Know more :-
Volume of cube = \sf a^3a
3
Volume of cuboid = \sf lbhlbh
CSA of cube = \sf 4a^24a
2
CSA of cuboid = \sf 2h(l+b)2h(l+b)
LSA of cube = \sf 6a^26a
2
LSA of cuboid = \sf 2(lb + bh + hl)2(lb+bh+hl)
\begin{gathered} \\ \end{gathered}
_____________________
@Sita05✨