One is asked to say a two digit number.
What is the probability of getting the first digit being smaller?
Answers
Answered by
4
No of favourable outcomes=36
No of possible outcome=90
Probability(P)=no of favourable outcomes/no of possible outcomes
P=36/90=4/10
PROBABILITY=2/5
Answered by
6
Answer:
The probability is 2/5.
Step-by-step explanation:
Let S be the sample space
S={10,11,12,13......99}
Event A is the event in which the probability of getting the number with first digit being smaller.
A={12,13,14,15,16,17,18,19,23,24,25,26,27,28,29,34,35,36,37,38,39,45,46,47,48,49,56,57,58,59,67,68,69,78,79,89}
p(A)= n(a)/n(S)= 36/90= 2/5
The probability of Event A is 2/5.
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