One kg of air in a closed system, initially at 5°C
and occupying 0.3 m3 volume, undergoes a
constant pressure heating process to 100°C.
There is no work other than pdv work. Find
i) The work done during the process.
ii) The heat transferred.
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Answers
Answer:
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Answer:
(i) The work done during the process is 243.4 Joules.
(ii) The heat transferred is 243.4 Joules.
Explanation:
From the ideal gas equation we have,
(1)
Where,
P=pressure at which the gas is present
V=volume occupied by the gas
n=number of moles of the gas
R=universal gas constant=0.082 L⋅atm⋅K⁻¹⋅mol⁻¹
T=temperature in kelvin
Equation (1) can also be written as,
(2)
(i) The work done during the process
And the work done is calculated as,
(3) (work done at constant pressure)
Using equation (2) in equation (3) we get;
(4)
From the question we have,
The mass of the air=1 kg=1×10³grams
The volume occupied by the gas(V)=0.3 m³
The initial temperature(T₁)=5°C=278K
The final temperature(T₂)=100°C=373K
Inserting all the required values in equation (4) we get;
(5)
The work done during the process is 243.4 Joules.
(ii) The heat transferred
From the first law of thermodynamics we have,
(6)
Where,
Q=heat transferred
ΔU=change in internal energy
W=work done during the process
Since the pressure is constant so internal energy will be constant.
So, equation (6) can be written as,
(7)
So, the heat transferred is 243.4 Joules.
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