One lamp ,one rated 100W at 220Volts .What is the resistance of the bulb???? Pls answer bathao
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In any electrical appliance their is a simple relationship between the power output of a component, the potential difference across that component, and the current running through it. This is because charge times potential difference is energy, so (charge per unit time) times (potential difference) gives (energy per unit time). Thus, we have P=VI.
Substituting I=V/R from ohm's law, the power relationship can be rewritten as P=RV2. From this formula, the resistance can be calculated as follows.
P=RV2 that is, R=PV2. The power and voltage are given as100W and 220V.
Therefore, R=1002202=10048400=484Ω.
Hence, the resistance of the bulb is 484 Ω.
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