Question

One lit of O2 effuses through a small
hole in 60min and one lit of another gas
X' at the same temperature and pressure
effuses through the same hole in 21.2
min. What is the atomic weight of 'X' ?
(A) 2.99
(B) 3.99
(C)
2.08
(D) 1.99​

Answer 1

Answer:There are 8:

Explanation:

1) O2

2) CO2

3) MgO

5) NO2

Answer 2

The atomic weight of X is equal to3.99

Explanation:

Given

• One litre of oxygen diffuses through a small hole in 60 minutes

• One litre of another gas diffuses through 21.2 minutes

• Hence the ratio of the effusion of the two gases p= 60/21.2 =2.83

• The Graham law of diffusion states that the the ratio of the diffusion rate of two gases is inversely proportional to the square root of their molecular weight.

• P= ✓ ( 32/x) , since 32 is the molecular weight of oxygen

• Hence x= 32/P²= 32/2.83²= 3.99

To know more,

The relative rate of effusion of ch4 to so2 through the container .

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