One liter of 750ppm solution of KClO3 contains how many grams of K+
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Answer:
7AM the name gopi says I am
Answered by
1
Explanation:
g/m3 = 1 mg/L =1 ppm
1 g/cm3 = 1,000,000 g/m3
0.77g/cm3 = 770,000 g/m3
770,000 g/m3 = 770,000 ppm
To prepare 1ppm of hexadecane in 1000 ml of water,
M1V1 = M2V2
(770000 ppm)V1 = (1ppm) 1000ml
V1 = 0.0013ml or 1.3 µl
If u don’t have the micro-pipette, u can prepare 1000ppm of hexadecane first then can dilute to 100, 10 and finally 1 ppm.
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