Question

One liter of a gas at 10oC is heated till both it’s volume and pressure are tripled . Find the new
temperature

Answer 1

Answer:

2274℃

Explanation:

10℃ = 283 K

P2 = 3P1

V2 = 3V1

using combined gas law

$\frac{p1v1}{t1} = \frac{p2v2}{t2}$

=> (P1 × V1)/(P2 × V2) = T1/ T2

=> 1/9 = 283/T2

=> T2 = 283 × 9 = 2547 K = 2274 ℃

Answer 2

Explanation:

hope it will help you bro