Question

one liter of an awueous solution contains 15g of the solute of molar mass 150g/mol if the density of solution is 1.005 g /mol .calculate mole fraction.​

Answer 1

Answer:

Given clearly that 1 molal of aqueous solution hence the solvent here is water. Therefore 1 mole solute present in the 1 kg of water. Molefraction is the ratio of the number of moles of solute and total number of moles in solution. Moles = (given mass) / (molar mass) = 1000/18 = 55.5 moles.

Answer 2

Answer:

hello dear,

Explanation:

Given clearly that 1 molal of aqueous solution hence the solvent here is water. Therefore 1 mole solute present in the 1 kg of water. Molefraction is the ratio of the number of moles of solute and total number of moles in solution. Moles = (given mass) / (molar mass) = 1000/18 = 55.5 moles.

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