one liter of water at 30c is mimed one liter of water at 50c the timp of the menture will be
Answers
Answer:
the temperature of the mixture of water will be 30+50/2°C = 80/2°C = 40°C
Answer:
therefore answer is 40°C.
Explanation:
Let the first volume of water be V1. Let the second volume of water be V2. Let the initial temperature of the first volume of water be θ1. Let the initial temperature of the second volume of water be θ2.
Let the energy required to heat a unit volume of water by unit temperature by C.
So, if the final temperature is θfinal, we have
heat gained by the first volume of water
=V
1
×C×(θ
final
−θ
1
)
and
heat lost by the second volume of water
=V
2
×C×(θ
2
−θ
final
).
By the law of conservation of energy,
heat lost = heat gained
∴V
1
×C×(θ
final
−θ
1
)=V
2
×C×(θ
2
−θ
final
)
∴V
1
θ
final
−V
1
θ
1
=V
2
θ
2
−V
2
θ
final
∴θ
final
=VI θ1+V2
θ2 V1+V 2
Substituting the given values,
θf final =2
30+50=40∘C.