Question

one litre aqueous solution of sucrose weighing 1015 gram has osmotic pressure of 4.82 atm. at 293 Kelvin find molality of solution​

Answer 1

0.211 is the molality of the solution.

Explanation:

Given,

Volume = 1 liter

Weight = 1015 g

Molar mass of solute = 342 per gram

Pressure (Π) = 4.82 atm

R = 0.0821 ltratm/Kmol

T = 293

As we know,

Π = CRT

4.82 =  C * 0.0821 * 293

C = 0.2

This shows that 1 liter of solution contains 0.2 sucrose moles. so,

w = 0.2 * 342

w = 68. 4g

Thus,

Weight of solvent = 1015 - 68.4

= 946.6 g or 0.946 kg

∵ Molality of the solution = No. of moles/weight of solvent in kg

= (68.4/342)/0.946

= 0.211 m

Learn more: Aqueous solution

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