Question

One litre N2, 7/8 litre O2 and 1 litre CO are taken in a mixture under indentical conditions of P and T. The amount of gases present in mixture is given by

Answer 1

Answer:

Wn2=Wo2>Wco

pls mark me as brainlist

if this was helpfull

Answer 2

The amount of gases present in the mixture is given by $w_{N_{2}}=w_{CO}=\frac{7}{256}w_{O_{2}}$

Explanation: The definition of an ideal gas is a gas in which there is no intermolecular force of attraction and collisions between molecules or atoms are entirely elastic. The four variables P, V, T, and the constant n serve as its representation. In this case, P stands for pressure, V for volume, T for temperature, and n for the total number of moles present. The relationship between these state variables is provided by the state equation.

The ideal gas equation is PV=nRT

Given, $N_2=1l$, $O_2=\frac{7}{8}l$, $CO=1l$

Also, P and T are constant.

We know, PV=nRT

At P and T constant, $V\propto n$

$\therefore m_{N_{2}}=m_{CO}=\frac{7}{8}m_{O_{2}}$

$\Rightarrow \frac{w_{N_{2}}}{28}=\frac{w_{CO}}{28}=\frac{\frac{7}{8}w_{O_{2}}}{32}\\\Rightarrow w_{N_{2}}=w_{CO}=\frac{7}{256}w_{O_{2}}$

To learn more about ideal gases, click on the links below:

https://brainly.in/question/7432529?msp_srt_exp=5

https://brainly.in/question/20698022?msp_srt_exp=5

#SPJ3