Question

One litre of 1 molar CuSO4 solution is electrolysed after passing 2 F charge what is molarity of CuSO4

Answer 1

hey ! mate here is your answer
For 1 M CuSo4 soln.,
moles x valence factor = q/F
therefore ,
1 × 1 × 2 = q/F
q = 2F
therefore , for passing 2F charge would consumed the soln . Completely and hence the Molarity becomes zero perhaps !
Hope it helps you !

Answer 2

Explanation:

The given data is as follows.

           Charge, q = 2F,         moles = 1

           valence factor = 1

It is known that relation between charge, valence factor and moles is as follows.

                Moles × Valence factor = $\frac{q}{F}$

Hence, putting the given values into the above formula as follows.

               Moles × Valence factor = $\frac{q}{F}$

                  1 × 1 = $\frac{2F}{F}$

The reaction equation will be as follows.

            $Cu^{2+} + 2e^{-} \rightarrow Cu$

Hence, pass 2F charge has consumed the solution. Therefore, we can conclude that molarity of the solution is 0.