Question

one litre of a gas at stp weighs 1.97g. what is the vapour density of the gas

Answer 1

1.97g occupies 1L volume, thus 22.4L will be occupied by : 1.97*22.4 / 1 = 44.128g

Since 1 mole of gas occupies 22.4L and weighs equal to it's molar mass, the molar mass of the gas is 44.128g/mol

Vapour density = Molar mass/2

Thus vapor density = 22.064

Answer 2

Answer:

obation A, 22.05 is perfect answer for this question