one litre of a gas at stp weighs 1.97g. what is the vapour density of the gas
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1.97g occupies 1L volume, thus 22.4L will be occupied by : 1.97*22.4 / 1 = 44.128g
Since 1 mole of gas occupies 22.4L and weighs equal to it's molar mass, the molar mass of the gas is 44.128g/mol
Vapour density = Molar mass/2
Thus vapor density = 22.064
Read more on Brainly.in - https://brainly.in/question/3789683#readmore
Since 1 mole of gas occupies 22.4L and weighs equal to it's molar mass, the molar mass of the gas is 44.128g/mol
Vapour density = Molar mass/2
Thus vapor density = 22.064
Read more on Brainly.in - https://brainly.in/question/3789683#readmore
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