One litre of a gas weighs 2g at 300k and 1atm pressurw.if the pressure is made 0.75 atm at which temperature will one litre of same gas weigh one gram
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The given data: P1 =1atm; V1 = 1L; P2 =0.75atm; V2 =1l; w1 =2 g; w1=1g; T1 = 300K; T2 =?
We know that, P1V1/T1 = P2V2/T2 or
P1V1/P2V2 = n1RT1/n2RT2 = w1RT1/w2RT2
Therefore, P1V1/P2V2 = w1RT1/w2RT2
1x1/0.75x1 = 2x 300/1xT2
T2 = 2x300x0.75
T2 = 450 K
We know that, P1V1/T1 = P2V2/T2 or
P1V1/P2V2 = n1RT1/n2RT2 = w1RT1/w2RT2
Therefore, P1V1/P2V2 = w1RT1/w2RT2
1x1/0.75x1 = 2x 300/1xT2
T2 = 2x300x0.75
T2 = 450 K
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