Question

One litre of a gas weighs 4g at 300 K and 1 atm. If the pressure is reduced to 0.75 atm, the temperan at which one litre of the same gas weights 2g is
1) 600 K
2) 900 K
3) 450 K
4) 800 K​

Answer 1

Answer:

450

P1V1/M1T1=P2V2/M2T2

1×1/4×300=1×0.75/2×T2

cross multiply

2T=900

T=450

here p means pressure v means volume M means mass T means temperature.