Chemistry, asked by explorerhills7602, 1 year ago

One litre of a gaseous mixture of two gases effus s in 311 sec while 2 litres of oxygen takes 20 mimutes . The vapour density and of the gaseous mixture containing ch4 and h2 is??

Answers

Answered by KaptainEasy
27

According to Graham's law of diffusion,

As rate of diffusion is inversely proportional to the square root of density that is

 \frac{r1}{r2}=\sqrt{}\frac{D2}{D1}

that is inversely proportional to square root of masses

 \frac{r1}{r2}=\sqrt{}\frac{M2}{M1}

that is inversely proportional to square root of vapour density

 \frac{r1}{r2}=\sqrt{}\frac{VD2}{VD1}

Rate of diffusion can be calculated as:

  r=\frac{v}{t}

where v is the volume of gas , while t is the time

So it will be:

 \frac{\frac{v1}{t1}}{\frac{v2}{t2}}=\sqrt{}\frac{M2}{M1}

putting the values:

 \frac{\frac{1}{311}}{\frac{2}{1200}}=\sqrt{}\frac{32}{M1}

M1 =4.30

2 \times vapour denity =molecular mass

vapour density=\frac{4.30}{2}

vapour density=2.15

Answered by Booshidha
8

Answer:

Hope this answer helps!!!!

Attachments:
Similar questions