Question

One litre of a gaseous mixture of two gases effuses in 311 seconds while 2 litres of oxygen takes 20 minutes. the vapour density of gaseous mixture containing ch4 and h2 is

Answer 1

We know that,

Rate of effusion ∝ volume

Rate of effusion ∝ $\frac{1}{time}$

Rate of effusion ∝ $\frac{1}{molar mass}$

On the basis of above relations,

$\frac{1*20*60}{2*311} = \sqrt{\frac{M(O2)}{M(CH_{4}) } }$

\sqrt{\frac{M(O2)}{M(CH_{4}) } }[/tex] = $\frac{1200}{622}</p><p>\sqrt{\frac{M(O2)}{M(CH_{4}) } }$ = 1.93

On squaring both side,

$\frac{M(O_{2}) }{M(CH_{4}) } =  3.72</p><p>Vapor density = [tex]Vapor  density = \frac{Molar mass}{2}$

$Vapor density of O_{2} = \frac{3.72}{2} =  1.86$

$Vapor density of (CH_{4}) = \frac{1}{2} = 0.5$