Question

One litre of a mixture of CO and CO2 is passed through red hot characoal in tube.The new volume becomes 1•4 litres .Find out percentage composition of mixture by volume .All measurements are made at same pressure and temperature?​

Answer 1

Explanation:

Equation of the reaction:

CO2 + C = 2CO

According to equation, when 1 litre of CO2 reacts with 1 mol of coke, twolitres of CO are formed. Our mixture of gases has volume 1.4 L. Thus it is

composed from CO and non-reacted CO2.

If x litres of CO2 are reacted, 2x liters of CO are formed. Total volume ofmixture is the sum of CO2 and CO volumes:

V(mixture) = V(new volume CO2) + V(CO) = 1.4 L

V(new volume CO2) = V(initial volume CO2) - V(reacted CO2) = (1 - x) L

V(CO) = 2x

So, we have equation:

1.4 = 1 - x + 2x

The solution is x = 0.4 L

Thus, the mixture consist from 1-0.4=0.6 L of CO2 and 2*0.4=0.8 L of CO (iii)

Answer: (iii)

The composition of product is 0.6 ltr of CO2 and 0.8 ltr of CO.