One litre of an aqueous solution of glucose ( molecular weight 180 ) contains 18 g of glucose. Calculate the strength of the solution in molarity.
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0.1 molal
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Given: One litre of an aqueous solution of glucose ( molecular weight 180 ) contains 18 g of glucose.
To find: Strength of the solution in molarity
Explanation: Given mass of glucose= 18 g
Molecular weight of glucose= 180 g
Let number of moles of glucose in solution be denoted as n.
Then,
n = Given mass of glucose / Molecular mass of glucose
= 18/ 180
= 0.1 moles
Volume of solution ( in Litres) = 1 L
Molarity= Number of moles/ Volume ( in L)
= 0.1 / 1
= 0.1 M
Therefore, the strength of the solution in molarity is 0.1 M.
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