One litre of an ideal gas is compressed isothermally at 0.72 m of hg column so that its volume becomes 0.9 l find its stress?
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Given:
initial pressure on gas P1=0.72m of Hg
Initial volume of gas =V1=1L
final volume of gas=V2=0.9L
Let P2 be the final pressure on Gas
From Boyle's law:P1V1=P2V2
P2=P1V1/V2
=0.72x1/0.9
=0.8m of Hg
So change in pressure is ΔP=P2-P1
=0.8-0.72
=0.08 m of Hg
Density of mercury=13600kg/m³
so ΔP=ρx gx0.08 N/m2
=13600x9.8x0.08
=10662.4 N/m2
As stress is defined as restoring force/area =pressure
Hence stress on gas is equal to change in pressure 10662.4 N/m²
initial pressure on gas P1=0.72m of Hg
Initial volume of gas =V1=1L
final volume of gas=V2=0.9L
Let P2 be the final pressure on Gas
From Boyle's law:P1V1=P2V2
P2=P1V1/V2
=0.72x1/0.9
=0.8m of Hg
So change in pressure is ΔP=P2-P1
=0.8-0.72
=0.08 m of Hg
Density of mercury=13600kg/m³
so ΔP=ρx gx0.08 N/m2
=13600x9.8x0.08
=10662.4 N/m2
As stress is defined as restoring force/area =pressure
Hence stress on gas is equal to change in pressure 10662.4 N/m²
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